I used the following expression for a sawtooth waveform to first generate the waveform mathematically and then try and remove the higher harmonics to band limit the signal and study the effect band-limiting had on the shape of the signal.

The MS Excel file is attached here

I set the Amplitude, A arbitrarily as 10 and the time frame from -10 to +10. Since I can’t possibly include infinite components I decided to go from k=1 to k=7 the expansion would then be as follows.

=((A2/2)–((A2/3.14)*(–SIN(2*3.14*100*B2)+((SIN(4*3.14*100*B2))/2)–((SIN(6*3.14*100*B2))/3)+((SIN(8*3.14

*100*B2))/4)–((SIN(10*3.14*100*B2))/5)+((SIN(12*3.14*100*B2))/6)–((SIN(14*3.14*100*B2))/7))))

This is the waveform for the signal with 6 harmonics.

**Plotting the signal as I keep on cutting down on the number of components.**

The equation for the signal with only the 1st component would look like this:

=((A2/2)–((A2/3.14)*(–SIN(2*3.14*100*B2)+(SIN(4*3.14*100*B2))/2)))

**And finally the band-limited signal: taking only the case: k=1 and neglecting all other higher harmonics.**

=((A2/2)+((A2/3.14)*SIN(2*3.14*100*B2)))

This would be the effect of a filter that removes all the higher components from a sawtooth waveform i.e it is reduced to a sine wave.

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